3(r+300)=63(r+300)=6

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Solution for 3(r+300)=63(r+300)=6 equation: 



3(r+300)=63(r+300)=6

We move all terms to the left:

3(r+300)-(63(r+300))=0

We multiply parentheses

3r-(63(r+300))+900=0



We calculate terms in parentheses: -(63(r+300)), so:

63(r+300)

We multiply parentheses

63r+18900

Back to the equation:

-(63r+18900)



We get rid of parentheses

3r-63r-18900+900=0

We add all the numbers together, and all the variables

-60r-18000=0

We move all terms containing r to the left, all other terms to the right

-60r=18000

r=18000/-60

r=-300

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