3(r+4)+2(r+5)=32

Solution for 3(r+4)+2(r+5)=32 equation:

Simplifying
3(r + 4) + 2(r + 5) = 32

Reorder the terms:
3(4 + r) + 2(r + 5) = 32
(4 * 3 + r * 3) + 2(r + 5) = 32
(12 + 3r) + 2(r + 5) = 32

Reorder the terms:
12 + 3r + 2(5 + r) = 32
12 + 3r + (5 * 2 + r * 2) = 32
12 + 3r + (10 + 2r) = 32

Reorder the terms:
12 + 10 + 3r + 2r = 32

Combine like terms: 12 + 10 = 22
22 + 3r + 2r = 32

Combine like terms: 3r + 2r = 5r
22 + 5r = 32

Solving
22 + 5r = 32

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-22' to each side of the equation.
22 + -22 + 5r = 32 + -22

Combine like terms: 22 + -22 = 0
0 + 5r = 32 + -22
5r = 32 + -22

Combine like terms: 32 + -22 = 10
5r = 10

Divide each side by '5'.
r = 2

Simplifying
r = 2