3(r+4)+2+40=2

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Solution for 3(r+4)+2+40=2 equation: 



3(r+4)+2+40=2

We move all terms to the left:

3(r+4)+2+40-(2)=0

We add all the numbers together, and all the variables

3(r+4)+40=0

We multiply parentheses

3r+12+40=0

We add all the numbers together, and all the variables

3r+52=0

We move all terms containing r to the left, all other terms to the right

3r=-52

r=-52/3

r=-17+1/3

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