3(r+4)+2r+40=2

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Solution for 3(r+4)+2r+40=2 equation: 



3(r+4)+2r+40=2

We move all terms to the left:

3(r+4)+2r+40-(2)=0

We add all the numbers together, and all the variables

2r+3(r+4)+38=0

We multiply parentheses

2r+3r+12+38=0

We add all the numbers together, and all the variables

5r+50=0

We move all terms containing r to the left, all other terms to the right

5r=-50

r=-50/5

r=-10

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