3(r+4)-11=28

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Solution for 3(r+4)-11=28 equation: 



3(r+4)-11=28

We move all terms to the left:

3(r+4)-11-(28)=0

We add all the numbers together, and all the variables

3(r+4)-39=0

We multiply parentheses

3r+12-39=0

We add all the numbers together, and all the variables

3r-27=0

We move all terms containing r to the left, all other terms to the right

3r=27

r=27/3

r=9

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