3(r+4)-2(r-4)=32

Solution for 3(r+4)-2(r-4)=32 equation:

Simplifying
3(r + 4) + -2(r + -4) = 32

Reorder the terms:
3(4 + r) + -2(r + -4) = 32
(4 * 3 + r * 3) + -2(r + -4) = 32
(12 + 3r) + -2(r + -4) = 32

Reorder the terms:
12 + 3r + -2(-4 + r) = 32
12 + 3r + (-4 * -2 + r * -2) = 32
12 + 3r + (8 + -2r) = 32

Reorder the terms:
12 + 8 + 3r + -2r = 32

Combine like terms: 12 + 8 = 20
20 + 3r + -2r = 32

Combine like terms: 3r + -2r = 1r
20 + 1r = 32

Solving
20 + 1r = 32

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + 1r = 32 + -20

Combine like terms: 20 + -20 = 0
0 + 1r = 32 + -20
1r = 32 + -20

Combine like terms: 32 + -20 = 12
1r = 12

Divide each side by '1'.
r = 12

Simplifying
r = 12