3(r+4)-r=2(r+a)

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Solution for 3(r+4)-r=2(r+a) equation:


Simplifying
3(r + 4) + -1r = 2(r + a)

Reorder the terms:
3(4 + r) + -1r = 2(r + a)
(4 * 3 + r * 3) + -1r = 2(r + a)
(12 + 3r) + -1r = 2(r + a)

Combine like terms: 3r + -1r = 2r
12 + 2r = 2(r + a)

Reorder the terms:
12 + 2r = 2(a + r)
12 + 2r = (a * 2 + r * 2)
12 + 2r = (2a + 2r)

Add '-2r' to each side of the equation.
12 + 2r + -2r = 2a + 2r + -2r

Combine like terms: 2r + -2r = 0
12 + 0 = 2a + 2r + -2r
12 = 2a + 2r + -2r

Combine like terms: 2r + -2r = 0
12 = 2a + 0
12 = 2a

Solving
12 = 2a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2a' to each side of the equation.
12 + -2a = 2a + -2a

Combine like terms: 2a + -2a = 0
12 + -2a = 0

Add '-12' to each side of the equation.
12 + -12 + -2a = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -2a = 0 + -12
-2a = 0 + -12

Combine like terms: 0 + -12 = -12
-2a = -12

Divide each side by '-2'.
a = 6

Simplifying
a = 6

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