3(r+4)=r-4

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Solution for 3(r+4)=r-4 equation:



3(r+4)=r-4
We move all terms to the left:
3(r+4)-(r-4)=0
We multiply parentheses
3r-(r-4)+12=0
We get rid of parentheses
3r-r+4+12=0
We add all the numbers together, and all the variables
2r+16=0
We move all terms containing r to the left, all other terms to the right
2r=-16
r=-16/2
r=-8

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