3(r+5)=2r+35

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Solution for 3(r+5)=2r+35 equation:


Simplifying
3(r + 5) = 2r + 35

Reorder the terms:
3(5 + r) = 2r + 35
(5 * 3 + r * 3) = 2r + 35
(15 + 3r) = 2r + 35

Reorder the terms:
15 + 3r = 35 + 2r

Solving
15 + 3r = 35 + 2r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-2r' to each side of the equation.
15 + 3r + -2r = 35 + 2r + -2r

Combine like terms: 3r + -2r = 1r
15 + 1r = 35 + 2r + -2r

Combine like terms: 2r + -2r = 0
15 + 1r = 35 + 0
15 + 1r = 35

Add '-15' to each side of the equation.
15 + -15 + 1r = 35 + -15

Combine like terms: 15 + -15 = 0
0 + 1r = 35 + -15
1r = 35 + -15

Combine like terms: 35 + -15 = 20
1r = 20

Divide each side by '1'.
r = 20

Simplifying
r = 20

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