3(r+6)+2=4(r+2)-21

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Solution for 3(r+6)+2=4(r+2)-21 equation: 



3(r+6)+2=4(r+2)-21

We move all terms to the left:

3(r+6)+2-(4(r+2)-21)=0

We multiply parentheses

3r-(4(r+2)-21)+18+2=0



We calculate terms in parentheses: -(4(r+2)-21), so:

4(r+2)-21

We multiply parentheses

4r+8-21

We add all the numbers together, and all the variables

4r-13

Back to the equation:

-(4r-13)



We add all the numbers together, and all the variables

3r-(4r-13)+20=0

We get rid of parentheses

3r-4r+13+20=0

We add all the numbers together, and all the variables

-1r+33=0

We move all terms containing r to the left, all other terms to the right

-r=-33

r=-33/-1

r=+33

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