3(r+s)+4(2r-s)=

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Solution for 3(r+s)+4(2r-s)= equation:


Simplifying
3(r + s) + 4(2r + -1s) = 0
(r * 3 + s * 3) + 4(2r + -1s) = 0
(3r + 3s) + 4(2r + -1s) = 0
3r + 3s + (2r * 4 + -1s * 4) = 0
3r + 3s + (8r + -4s) = 0

Reorder the terms:
3r + 8r + 3s + -4s = 0

Combine like terms: 3r + 8r = 11r
11r + 3s + -4s = 0

Combine like terms: 3s + -4s = -1s
11r + -1s = 0

Solving
11r + -1s = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add 's' to each side of the equation.
11r + -1s + s = 0 + s

Combine like terms: -1s + s = 0
11r + 0 = 0 + s
11r = 0 + s
Remove the zero:
11r = s

Divide each side by '11'.
r = 0.09090909091s

Simplifying
r = 0.09090909091s

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