3(r-1)=2(2+r)

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Solution for 3(r-1)=2(2+r) equation: 



3(r-1)=2(2+r)

We move all terms to the left:

3(r-1)-(2(2+r))=0

We add all the numbers together, and all the variables

3(r-1)-(2(r+2))=0

We multiply parentheses

3r-(2(r+2))-3=0



We calculate terms in parentheses: -(2(r+2)), so:

2(r+2)

We multiply parentheses

2r+4

Back to the equation:

-(2r+4)



We get rid of parentheses

3r-2r-4-3=0

We add all the numbers together, and all the variables

r-7=0

We move all terms containing r to the left, all other terms to the right

r=7

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