3(r-1)=2(r+3)

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Solution for 3(r-1)=2(r+3) equation: 



3(r-1)=2(r+3)

We move all terms to the left:

3(r-1)-(2(r+3))=0

We multiply parentheses

3r-(2(r+3))-3=0



We calculate terms in parentheses: -(2(r+3)), so:

2(r+3)

We multiply parentheses

2r+6

Back to the equation:

-(2r+6)



We get rid of parentheses

3r-2r-6-3=0

We add all the numbers together, and all the variables

r-9=0

We move all terms containing r to the left, all other terms to the right

r=9

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