3(r-15)+4r=6

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Solution for 3(r-15)+4r=6 equation: 



3(r-15)+4r=6

We move all terms to the left:

3(r-15)+4r-(6)=0

We add all the numbers together, and all the variables

4r+3(r-15)-6=0

We multiply parentheses

4r+3r-45-6=0

We add all the numbers together, and all the variables

7r-51=0

We move all terms containing r to the left, all other terms to the right

7r=51

r=51/7

r=7+2/7

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