3(r-2)+4=19

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Solution for 3(r-2)+4=19 equation: 



3(r-2)+4=19

We move all terms to the left:

3(r-2)+4-(19)=0

We add all the numbers together, and all the variables

3(r-2)-15=0

We multiply parentheses

3r-6-15=0

We add all the numbers together, and all the variables

3r-21=0

We move all terms containing r to the left, all other terms to the right

3r=21

r=21/3

r=7

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