3(r-3)=7(2+4r)

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Solution for 3(r-3)=7(2+4r) equation: 



3(r-3)=7(2+4r)

We move all terms to the left:

3(r-3)-(7(2+4r))=0

We add all the numbers together, and all the variables

3(r-3)-(7(4r+2))=0

We multiply parentheses

3r-(7(4r+2))-9=0



We calculate terms in parentheses: -(7(4r+2)), so:

7(4r+2)

We multiply parentheses

28r+14

Back to the equation:

-(28r+14)



We get rid of parentheses

3r-28r-14-9=0

We add all the numbers together, and all the variables

-25r-23=0

We move all terms containing r to the left, all other terms to the right

-25r=23

r=23/-25

r=-23/25

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