3(r-4)-14=2(r-7)+7

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Solution for 3(r-4)-14=2(r-7)+7 equation: 



3(r-4)-14=2(r-7)+7

We move all terms to the left:

3(r-4)-14-(2(r-7)+7)=0

We multiply parentheses

3r-(2(r-7)+7)-12-14=0



We calculate terms in parentheses: -(2(r-7)+7), so:

2(r-7)+7

We multiply parentheses

2r-14+7

We add all the numbers together, and all the variables

2r-7

Back to the equation:

-(2r-7)



We add all the numbers together, and all the variables

3r-(2r-7)-26=0

We get rid of parentheses

3r-2r+7-26=0

We add all the numbers together, and all the variables

r-19=0

We move all terms containing r to the left, all other terms to the right

r=19

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