3(r-4)=-12+3r

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Solution for 3(r-4)=-12+3r equation: 



3(r-4)=-12+3r

We move all terms to the left:

3(r-4)-(-12+3r)=0

We add all the numbers together, and all the variables

3(r-4)-(3r-12)=0

We multiply parentheses

3r-(3r-12)-12=0

We get rid of parentheses

3r-3r+12-12=0

We add all the numbers together, and all the variables

=0

r=0/1

r=0

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