3(r-4)=2r-3+4r

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Solution for 3(r-4)=2r-3+4r equation: 



3(r-4)=2r-3+4r

We move all terms to the left:

3(r-4)-(2r-3+4r)=0

We add all the numbers together, and all the variables

3(r-4)-(6r-3)=0

We multiply parentheses

3r-(6r-3)-12=0

We get rid of parentheses

3r-6r+3-12=0

We add all the numbers together, and all the variables

-3r-9=0

We move all terms containing r to the left, all other terms to the right

-3r=9

r=9/-3

r=-3

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