3(r-4)=32-12

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Solution for 3(r-4)=32-12 equation: 



3(r-4)=32-12

We move all terms to the left:

3(r-4)-(32-12)=0

We add all the numbers together, and all the variables

3(r-4)-20=0

We multiply parentheses

3r-12-20=0

We add all the numbers together, and all the variables

3r-32=0

We move all terms containing r to the left, all other terms to the right

3r=32

r=32/3

r=10+2/3

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