3(r-4)=7(r+2)-2

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Solution for 3(r-4)=7(r+2)-2 equation:


Simplifying
3(r + -4) = 7(r + 2) + -2

Reorder the terms:
3(-4 + r) = 7(r + 2) + -2
(-4 * 3 + r * 3) = 7(r + 2) + -2
(-12 + 3r) = 7(r + 2) + -2

Reorder the terms:
-12 + 3r = 7(2 + r) + -2
-12 + 3r = (2 * 7 + r * 7) + -2
-12 + 3r = (14 + 7r) + -2

Reorder the terms:
-12 + 3r = 14 + -2 + 7r

Combine like terms: 14 + -2 = 12
-12 + 3r = 12 + 7r

Solving
-12 + 3r = 12 + 7r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-7r' to each side of the equation.
-12 + 3r + -7r = 12 + 7r + -7r

Combine like terms: 3r + -7r = -4r
-12 + -4r = 12 + 7r + -7r

Combine like terms: 7r + -7r = 0
-12 + -4r = 12 + 0
-12 + -4r = 12

Add '12' to each side of the equation.
-12 + 12 + -4r = 12 + 12

Combine like terms: -12 + 12 = 0
0 + -4r = 12 + 12
-4r = 12 + 12

Combine like terms: 12 + 12 = 24
-4r = 24

Divide each side by '-4'.
r = -6

Simplifying
r = -6

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