3(r-5)=-16+2r

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Solution for 3(r-5)=-16+2r equation: 



3(r-5)=-16+2r

We move all terms to the left:

3(r-5)-(-16+2r)=0

We add all the numbers together, and all the variables

3(r-5)-(2r-16)=0

We multiply parentheses

3r-(2r-16)-15=0

We get rid of parentheses

3r-2r+16-15=0

We add all the numbers together, and all the variables

r+1=0

We move all terms containing r to the left, all other terms to the right

r=-1

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