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3(r-5)=5r-(3-r)
We move all terms to the left:
3(r-5)-(5r-(3-r))=0
We add all the numbers together, and all the variables
3(r-5)-(5r-(-1r+3))=0
We multiply parentheses
3r-(5r-(-1r+3))-15=0
We calculate terms in parentheses: -(5r-(-1r+3)), so:We get rid of parentheses
5r-(-1r+3)
We get rid of parentheses
5r+1r-3
We add all the numbers together, and all the variables
6r-3
Back to the equation:
-(6r-3)
3r-6r+3-15=0
We add all the numbers together, and all the variables
-3r-12=0
We move all terms containing r to the left, all other terms to the right
-3r=12
r=12/-3
r=-4
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