3(r-6)+2=2(r+2)-21

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Solution for 3(r-6)+2=2(r+2)-21 equation: 


Simplifying
3(r + -6) + 2 = 2(r + 2) + -21

Reorder the terms:
3(-6 + r) + 2 = 2(r + 2) + -21
(-6 * 3 + r * 3) + 2 = 2(r + 2) + -21
(-18 + 3r) + 2 = 2(r + 2) + -21

Reorder the terms:
-18 + 2 + 3r = 2(r + 2) + -21

Combine like terms: -18 + 2 = -16
-16 + 3r = 2(r + 2) + -21

Reorder the terms:
-16 + 3r = 2(2 + r) + -21
-16 + 3r = (2 * 2 + r * 2) + -21
-16 + 3r = (4 + 2r) + -21

Reorder the terms:
-16 + 3r = 4 + -21 + 2r

Combine like terms: 4 + -21 = -17
-16 + 3r = -17 + 2r

Solving
-16 + 3r = -17 + 2r

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-2r' to each side of the equation.
-16 + 3r + -2r = -17 + 2r + -2r

Combine like terms: 3r + -2r = 1r
-16 + 1r = -17 + 2r + -2r

Combine like terms: 2r + -2r = 0
-16 + 1r = -17 + 0
-16 + 1r = -17

Add '16' to each side of the equation.
-16 + 16 + 1r = -17 + 16

Combine like terms: -16 + 16 = 0
0 + 1r = -17 + 16
1r = -17 + 16

Combine like terms: -17 + 16 = -1
1r = -1

Divide each side by '1'.
r = -1

Simplifying
r = -1

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