3(r-6)+2=4(r+2)-21=

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Solution for 3(r-6)+2=4(r+2)-21= equation: 



3(r-6)+2=4(r+2)-21=

We move all terms to the left:

3(r-6)+2-(4(r+2)-21)=0

We multiply parentheses

3r-(4(r+2)-21)-18+2=0



We calculate terms in parentheses: -(4(r+2)-21), so:

4(r+2)-21

We multiply parentheses

4r+8-21

We add all the numbers together, and all the variables

4r-13

Back to the equation:

-(4r-13)



We add all the numbers together, and all the variables

3r-(4r-13)-16=0

We get rid of parentheses

3r-4r+13-16=0

We add all the numbers together, and all the variables

-1r-3=0

We move all terms containing r to the left, all other terms to the right

-r=3

r=3/-1

r=-3

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