3(r-6)+2=4(r+2)-22

Solution for 3(r-6)+2=4(r+2)-22 equation:

3(r-6)+2=4(r+2)-22

We move all terms to the left:

3(r-6)+2-(4(r+2)-22)=0

We multiply parentheses

3r-(4(r+2)-22)-18+2=0


We calculate terms in parentheses: -(4(r+2)-22), so:

4(r+2)-22

We multiply parentheses

4r+8-22

We add all the numbers together, and all the variables

4r-14

Back to the equation:

-(4r-14)


We add all the numbers together, and all the variables

3r-(4r-14)-16=0

We get rid of parentheses

3r-4r+14-16=0

We add all the numbers together, and all the variables

-1r-2=0

We move all terms containing r to the left, all other terms to the right

-r=2

r=2/-1

r=-2