3(r-6)+3=-6r+30

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Solution for 3(r-6)+3=-6r+30 equation: 



3(r-6)+3=-6r+30

We move all terms to the left:

3(r-6)+3-(-6r+30)=0

We multiply parentheses

3r-(-6r+30)-18+3=0

We get rid of parentheses

3r+6r-30-18+3=0

We add all the numbers together, and all the variables

9r-45=0

We move all terms containing r to the left, all other terms to the right

9r=45

r=45/9

r=5

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