3(r-7)+2r=5(r-2)

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Solution for 3(r-7)+2r=5(r-2) equation: 



3(r-7)+2r=5(r-2)

We move all terms to the left:

3(r-7)+2r-(5(r-2))=0

We add all the numbers together, and all the variables

2r+3(r-7)-(5(r-2))=0

We multiply parentheses

2r+3r-(5(r-2))-21=0



We calculate terms in parentheses: -(5(r-2)), so:

5(r-2)

We multiply parentheses

5r-10

Back to the equation:

-(5r-10)



We add all the numbers together, and all the variables

5r-(5r-10)-21=0

We get rid of parentheses

5r-5r+10-21=0

We add all the numbers together, and all the variables

-11!=0

There is no solution for this equation

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