3(r-8)-(r-4)=3(r+5)+3

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Solution for 3(r-8)-(r-4)=3(r+5)+3 equation:



3(r-8)-(r-4)=3(r+5)+3
We move all terms to the left:
3(r-8)-(r-4)-(3(r+5)+3)=0
We multiply parentheses
3r-(r-4)-(3(r+5)+3)-24=0
We get rid of parentheses
3r-r-(3(r+5)+3)+4-24=0
We calculate terms in parentheses: -(3(r+5)+3), so:
3(r+5)+3
We multiply parentheses
3r+15+3
We add all the numbers together, and all the variables
3r+18
Back to the equation:
-(3r+18)
We add all the numbers together, and all the variables
2r-(3r+18)-20=0
We get rid of parentheses
2r-3r-18-20=0
We add all the numbers together, and all the variables
-1r-38=0
We move all terms containing r to the left, all other terms to the right
-r=38
r=38/-1
r=-38

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