3(r-8)-(r-4)=3(r+5)+3

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Solution for 3(r-8)-(r-4)=3(r+5)+3 equation: 



3(r-8)-(r-4)=3(r+5)+3

We move all terms to the left:

3(r-8)-(r-4)-(3(r+5)+3)=0

We multiply parentheses

3r-(r-4)-(3(r+5)+3)-24=0

We get rid of parentheses

3r-r-(3(r+5)+3)+4-24=0



We calculate terms in parentheses: -(3(r+5)+3), so:

3(r+5)+3

We multiply parentheses

3r+15+3

We add all the numbers together, and all the variables

3r+18

Back to the equation:

-(3r+18)



We add all the numbers together, and all the variables

2r-(3r+18)-20=0

We get rid of parentheses

2r-3r-18-20=0

We add all the numbers together, and all the variables

-1r-38=0

We move all terms containing r to the left, all other terms to the right

-r=38

r=38/-1

r=-38

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