3(s+1)-(s+1)2=10-(5-3s)

Solution for 3(s+1)-(s+1)2=10-(5-3s) equation:

3(s+1)-(s+1)2=10-(5-3s)

We move all terms to the left:

3(s+1)-(s+1)2-(10-(5-3s))=0

We add all the numbers together, and all the variables

3(s+1)-(s+1)2-(10-(-3s+5))=0

We multiply parentheses

3s-2s-(10-(-3s+5))+3-2=0


We calculate terms in parentheses: -(10-(-3s+5)), so:

10-(-3s+5)

determiningTheFunctionDomain
-(-3s+5)+10

We get rid of parentheses

3s-5+10

We add all the numbers together, and all the variables

3s+5

Back to the equation:

-(3s+5)


We add all the numbers together, and all the variables

s-(3s+5)+1=0

We get rid of parentheses

s-3s-5+1=0

We add all the numbers together, and all the variables

-2s-4=0

We move all terms containing s to the left, all other terms to the right

-2s=4

s=4/-2

s=-2