3(s+1)-(s-z)=22s

Solution for 3(s+1)-(s-z)=22s equation:

Simplifying
3(s + 1) + -1(s + -1z) = 22s

Reorder the terms:
3(1 + s) + -1(s + -1z) = 22s
(1 * 3 + s * 3) + -1(s + -1z) = 22s
(3 + 3s) + -1(s + -1z) = 22s
3 + 3s + (s * -1 + -1z * -1) = 22s
3 + 3s + (-1s + 1z) = 22s

Combine like terms: 3s + -1s = 2s
3 + 2s + 1z = 22s

Solving
3 + 2s + 1z = 22s

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-22s' to each side of the equation.
3 + 2s + -22s + 1z = 22s + -22s

Combine like terms: 2s + -22s = -20s
3 + -20s + 1z = 22s + -22s

Combine like terms: 22s + -22s = 0
3 + -20s + 1z = 0

Add '-3' to each side of the equation.
3 + -20s + -3 + 1z = 0 + -3

Reorder the terms:
3 + -3 + -20s + 1z = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -20s + 1z = 0 + -3
-20s + 1z = 0 + -3

Combine like terms: 0 + -3 = -3
-20s + 1z = -3

Add '-1z' to each side of the equation.
-20s + 1z + -1z = -3 + -1z

Combine like terms: 1z + -1z = 0
-20s + 0 = -3 + -1z
-20s = -3 + -1z

Divide each side by '-20'.
s = 0.15 + 0.05z

Simplifying
s = 0.15 + 0.05z