3(s+1)-8=6s(2-4)

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Solution for 3(s+1)-8=6s(2-4) equation: 



3(s+1)-8=6s(2-4)

We move all terms to the left:

3(s+1)-8-(6s(2-4))=0

We add all the numbers together, and all the variables

3(s+1)-(6s(-2))-8=0

We multiply parentheses

3s-(6s(-2))+3-8=0



We calculate terms in parentheses: -(6s(-2)), so:

6s(-2)

We multiply parentheses

-12s

Back to the equation:

-(-12s)



We add all the numbers together, and all the variables

3s-(-12s)-5=0

We get rid of parentheses

3s+12s-5=0

We add all the numbers together, and all the variables

15s-5=0

We move all terms containing s to the left, all other terms to the right

15s=5

s=5/15

s=1/3

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