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3(s-16)+-11=1
We move all terms to the left:
3(s-16)+-11-(1)=0
determiningTheFunctionDomain 3(s-16)-11-1+=0
We add all the numbers together, and all the variables
3(s-16)=0
We multiply parentheses
3s-48=0
We move all terms containing s to the left, all other terms to the right
3s=48
s=48/3
s=16
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