3(s-2)+1=4+2s

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Solution for 3(s-2)+1=4+2s equation: 



3(s-2)+1=4+2s

We move all terms to the left:

3(s-2)+1-(4+2s)=0

We add all the numbers together, and all the variables

3(s-2)-(2s+4)+1=0

We multiply parentheses

3s-(2s+4)-6+1=0

We get rid of parentheses

3s-2s-4-6+1=0

We add all the numbers together, and all the variables

s-9=0

We move all terms containing s to the left, all other terms to the right

s=9

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