3(s-3)=5(2s+1)

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Solution for 3(s-3)=5(2s+1) equation: 



3(s-3)=5(2s+1)

We move all terms to the left:

3(s-3)-(5(2s+1))=0

We multiply parentheses

3s-(5(2s+1))-9=0



We calculate terms in parentheses: -(5(2s+1)), so:

5(2s+1)

We multiply parentheses

10s+5

Back to the equation:

-(10s+5)



We get rid of parentheses

3s-10s-5-9=0

We add all the numbers together, and all the variables

-7s-14=0

We move all terms containing s to the left, all other terms to the right

-7s=14

s=14/-7

s=-2

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