3(s2)+s=38

Solution for 3(s2)+s=38 equation:

3(s2)+s=38

We move all terms to the left:

3(s2)+s-(38)=0

We add all the numbers together, and all the variables

3s^2+s-38=0

a = 3; b = 1; c = -38;
Δ = b2-4ac
Δ = 12-4·3·(-38)
Δ = 457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{457}}{2*3}=\frac{-1-\sqrt{457}}{6}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{457}}{2*3}=\frac{-1+\sqrt{457}}{6}
$