3(sin(x)+cos(x))=2cos(x)

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Solution for 3(sin(x)+cos(x))=2cos(x) equation:


Simplifying
3(sin(x) + cos(x)) = 2cos(x)

Multiply ins * x
3(insx + cos(x)) = 2cos(x)

Multiply cos * x
3(insx + cosx) = 2cos(x)

Reorder the terms:
3(cosx + insx) = 2cos(x)
(cosx * 3 + insx * 3) = 2cos(x)
(3cosx + 3insx) = 2cos(x)

Multiply cos * x
3cosx + 3insx = 2cosx

Solving
3cosx + 3insx = 2cosx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2cosx' to each side of the equation.
3cosx + -2cosx + 3insx = 2cosx + -2cosx

Combine like terms: 3cosx + -2cosx = 1cosx
1cosx + 3insx = 2cosx + -2cosx

Combine like terms: 2cosx + -2cosx = 0
1cosx + 3insx = 0

Add '-3insx' to each side of the equation.
1cosx + 3insx + -3insx = 0 + -3insx

Combine like terms: 3insx + -3insx = 0
1cosx + 0 = 0 + -3insx
1cosx = 0 + -3insx
Remove the zero:
1cosx = -3insx

Divide each side by '1osx'.
c = -3ino-1

Simplifying
c = -3ino-1

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