3(t+1)-3(4t+2)=-3-10t

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Solution for 3(t+1)-3(4t+2)=-3-10t equation: 



3(t+1)-3(4t+2)=-3-10t

We move all terms to the left:

3(t+1)-3(4t+2)-(-3-10t)=0

We add all the numbers together, and all the variables

3(t+1)-3(4t+2)-(-10t-3)=0

We multiply parentheses

3t-12t-(-10t-3)+3-6=0

We get rid of parentheses

3t-12t+10t+3+3-6=0

We add all the numbers together, and all the variables

t=0

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