3(t+1)-t=2(t+5)

Solution for 3(t+1)-t=2(t+5) equation:

Simplifying
3(t + 1) + -1t = 2(t + 5)

Reorder the terms:
3(1 + t) + -1t = 2(t + 5)
(1 * 3 + t * 3) + -1t = 2(t + 5)
(3 + 3t) + -1t = 2(t + 5)

Combine like terms: 3t + -1t = 2t
3 + 2t = 2(t + 5)

Reorder the terms:
3 + 2t = 2(5 + t)
3 + 2t = (5 * 2 + t * 2)
3 + 2t = (10 + 2t)

Add '-2t' to each side of the equation.
3 + 2t + -2t = 10 + 2t + -2t

Combine like terms: 2t + -2t = 0
3 + 0 = 10 + 2t + -2t
3 = 10 + 2t + -2t

Combine like terms: 2t + -2t = 0
3 = 10 + 0
3 = 10

Solving
3 = 10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.