3(t+1)=5(2t-5)

Solution for 3(t+1)=5(2t-5) equation:

Simplifying
3(t + 1) = 5(2t + -5)

Reorder the terms:
3(1 + t) = 5(2t + -5)
(1 * 3 + t * 3) = 5(2t + -5)
(3 + 3t) = 5(2t + -5)

Reorder the terms:
3 + 3t = 5(-5 + 2t)
3 + 3t = (-5 * 5 + 2t * 5)
3 + 3t = (-25 + 10t)

Solving
3 + 3t = -25 + 10t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-10t' to each side of the equation.
3 + 3t + -10t = -25 + 10t + -10t

Combine like terms: 3t + -10t = -7t
3 + -7t = -25 + 10t + -10t

Combine like terms: 10t + -10t = 0
3 + -7t = -25 + 0
3 + -7t = -25

Add '-3' to each side of the equation.
3 + -3 + -7t = -25 + -3

Combine like terms: 3 + -3 = 0
0 + -7t = -25 + -3
-7t = -25 + -3

Combine like terms: -25 + -3 = -28
-7t = -28

Divide each side by '-7'.
t = 4

Simplifying
t = 4