3(t+2)+4(t-1)=72

Solution for 3(t+2)+4(t-1)=72 equation:

Simplifying
3(t + 2) + 4(t + -1) = 72

Reorder the terms:
3(2 + t) + 4(t + -1) = 72
(2 * 3 + t * 3) + 4(t + -1) = 72
(6 + 3t) + 4(t + -1) = 72

Reorder the terms:
6 + 3t + 4(-1 + t) = 72
6 + 3t + (-1 * 4 + t * 4) = 72
6 + 3t + (-4 + 4t) = 72

Reorder the terms:
6 + -4 + 3t + 4t = 72

Combine like terms: 6 + -4 = 2
2 + 3t + 4t = 72

Combine like terms: 3t + 4t = 7t
2 + 7t = 72

Solving
2 + 7t = 72

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 7t = 72 + -2

Combine like terms: 2 + -2 = 0
0 + 7t = 72 + -2
7t = 72 + -2

Combine like terms: 72 + -2 = 70
7t = 70

Divide each side by '7'.
t = 10

Simplifying
t = 10