3(t+2)=1=8

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Solution for 3(t+2)=1=8 equation: 



3(t+2)=1=8

We move all terms to the left:

3(t+2)-(1)=0

We multiply parentheses

3t+6-1=0

We add all the numbers together, and all the variables

3t+5=0

We move all terms containing t to the left, all other terms to the right

3t=-5

t=-5/3

t=-1+2/3

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