3(t+2)=2(1-t)

Solution for 3(t+2)=2(1-t) equation:

3(t+2)=2(1-t)

We move all terms to the left:

3(t+2)-(2(1-t))=0

We add all the numbers together, and all the variables

3(t+2)-(2(-1t+1))=0

We multiply parentheses

3t-(2(-1t+1))+6=0


We calculate terms in parentheses: -(2(-1t+1)), so:

2(-1t+1)

We multiply parentheses

-2t+2

Back to the equation:

-(-2t+2)


We get rid of parentheses

3t+2t-2+6=0

We add all the numbers together, and all the variables

5t+4=0

We move all terms containing t to the left, all other terms to the right

5t=-4

t=-4/5

t=-4/5