3(t+2)=2(13-t)

Solution for 3(t+2)=2(13-t) equation:

3(t+2)=2(13-t)

We move all terms to the left:

3(t+2)-(2(13-t))=0

We add all the numbers together, and all the variables

3(t+2)-(2(-1t+13))=0

We multiply parentheses

3t-(2(-1t+13))+6=0


We calculate terms in parentheses: -(2(-1t+13)), so:

2(-1t+13)

We multiply parentheses

-2t+26

Back to the equation:

-(-2t+26)


We get rid of parentheses

3t+2t-26+6=0

We add all the numbers together, and all the variables

5t-20=0

We move all terms containing t to the left, all other terms to the right

5t=20

t=20/5

t=4