3(t+2)=t+5(2t+1)

Solution for 3(t+2)=t+5(2t+1) equation:

3(t+2)=t+5(2t+1)

We move all terms to the left:

3(t+2)-(t+5(2t+1))=0

We multiply parentheses

3t-(t+5(2t+1))+6=0


We calculate terms in parentheses: -(t+5(2t+1)), so:

t+5(2t+1)

We multiply parentheses

t+10t+5

We add all the numbers together, and all the variables

11t+5

Back to the equation:

-(11t+5)


We get rid of parentheses

3t-11t-5+6=0

We add all the numbers together, and all the variables

-8t+1=0

We move all terms containing t to the left, all other terms to the right

-8t=-1

t=-1/-8

t=1/8