3(t+3t)=28-2t

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Solution for 3(t+3t)=28-2t equation: 



3(t+3t)=28-2t

We move all terms to the left:

3(t+3t)-(28-2t)=0

We add all the numbers together, and all the variables

3(+4t)-(-2t+28)=0

We multiply parentheses

12t-(-2t+28)=0

We get rid of parentheses

12t+2t-28=0

We add all the numbers together, and all the variables

14t-28=0

We move all terms containing t to the left, all other terms to the right

14t=28

t=28/14

t=2

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