3(t+4)-2(2t+3)=-4+t

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Solution for 3(t+4)-2(2t+3)=-4+t equation: 



3(t+4)-2(2t+3)=-4+t

We move all terms to the left:

3(t+4)-2(2t+3)-(-4+t)=0

We add all the numbers together, and all the variables

3(t+4)-2(2t+3)-(t-4)=0

We multiply parentheses

3t-4t-(t-4)+12-6=0

We get rid of parentheses

3t-4t-t+4+12-6=0

We add all the numbers together, and all the variables

-2t+10=0

We move all terms containing t to the left, all other terms to the right

-2t=-10

t=-10/-2

t=+5

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