3(t+4)=t+13

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Solution for 3(t+4)=t+13 equation: 



3(t+4)=t+13

We move all terms to the left:

3(t+4)-(t+13)=0

We multiply parentheses

3t-(t+13)+12=0

We get rid of parentheses

3t-t-13+12=0

We add all the numbers together, and all the variables

2t-1=0

We move all terms containing t to the left, all other terms to the right

2t=1

t=1/2

t=1/2

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