3(t+41)=-15(3-t)

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Solution for 3(t+41)=-15(3-t) equation: 



3(t+41)=-15(3-t)

We move all terms to the left:

3(t+41)-(-15(3-t))=0

We add all the numbers together, and all the variables

3(t+41)-(-15(-1t+3))=0

We multiply parentheses

3t-(-15(-1t+3))+123=0



We calculate terms in parentheses: -(-15(-1t+3)), so:

-15(-1t+3)

We multiply parentheses

15t-45

Back to the equation:

-(15t-45)



We get rid of parentheses

3t-15t+45+123=0

We add all the numbers together, and all the variables

-12t+168=0

We move all terms containing t to the left, all other terms to the right

-12t=-168

t=-168/-12

t=+14

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