3(t+5)+4t-2=20

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Solution for 3(t+5)+4t-2=20 equation: 



3(t+5)+4t-2=20

We move all terms to the left:

3(t+5)+4t-2-(20)=0

We add all the numbers together, and all the variables

4t+3(t+5)-22=0

We multiply parentheses

4t+3t+15-22=0

We add all the numbers together, and all the variables

7t-7=0

We move all terms containing t to the left, all other terms to the right

7t=7

t=7/7

t=1

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